A) \[5.5\,mH\]
B) \[0.55\,mH\]
C) \[55\text{ }mH\]
D) \[~0.55\text{ }H.\]
Correct Answer: D
Solution :
\[Z=\sqrt{{{10}^{2}}+{{({{X}_{L}}-{{X}_{C}})}^{2}}}\] \[{{X}_{L}}=2000\times 5\times {{10}^{-3}}=10\,\Omega \] \[{{X}_{C}}=\frac{1}{WC}=\frac{1}{2000\times 50\times {{10}^{-6}}}=10\,\Omega \] \[Z=\sqrt{{{10}^{2}}+0}=10\,\Omega \] Reading of ammeter\[=\frac{V}{R}=\frac{20}{10}\] \[{{i}_{\max }}=2\,amp.\] \[{{i}_{r.m.s.}}=\frac{2}{\sqrt{2}}=1.41\,\text{amp}\text{.}\] \[{{V}_{r.m.s.}}=4\times 1.41=5.64\,V\]
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