A) the magnet moves with continuously decreasing velocity and ultimately comes to rest
B) the magnet moves with continuously increasing velocity and ultimately acquires a constant terminal velocity
C) the magnet moves with continuously increasing velocity and acceleration
D) the magnet moves with continuously increasing velocity but constant acceleration.
Correct Answer: B
Solution :
\[\frac{1}{\lambda }=R\left( \frac{1}{n{{f}^{2}}}-\frac{1}{n{{i}^{2}}} \right)\] Balmer series lies in emission spectra. \[{{n}_{i}}=3\] \[{{n}_{f}}=2\] When electron jumps from \[n=3\]to \[n=2\]and emit a photon. Then to fill of this vacancy created by an\[\bar{e}\]jump another\[\bar{e}\]from any excited state jump to\[n=1\]state and there by emitted a photon whose energy is equal to the difference between the two levels. After \[{{10}^{-8}}\sec \]both return to their original position. Then also emit photons process continue and we observe line spectrum. Hence one photon emitted in Balmer series. Then\[{{\text{H}}_{\text{2}}}\]atom must emit another photon in Lymen series.
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