CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2001

  • question_answer
    In a group (G, *) for some a of \[G,{{a}^{2}}=e,\]where e is the identity. Then:

    A)  \[a=\sqrt{e}\]                  

    B) \[a={{a}^{-1}}\]

    C)  \[a=e\]                               

    D)  none of these

    Correct Answer: B

    Solution :

    \[{{a}^{2}}=e\Rightarrow {{a}^{-1}}({{a}^{2}})={{a}^{-1}}e\Rightarrow a={{a}^{-1}}\]


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