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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2001

  • question_answer
    The equation\[{{\sin }^{2}}\theta =\frac{{{x}^{2}}+{{y}^{2}}}{2xy},\] possible if:

    A) \[~x=y\]                              

    B)  \[x=-y\]

    C) \[2x=y\]                              

    D)  none of these

    Correct Answer: A

    Solution :

    \[{{\sin }^{2}}\theta =\frac{{{x}^{2}}+{{y}^{2}}}{2xy}\] \[\Rightarrow \]\[{{(\pm \,1)}^{2}}=\frac{{{x}^{2}}+{{y}^{2}}}{2xy}\] \[\Rightarrow \]\[{{x}^{2}}+{{y}^{2}}=2xy\] \[{{x}^{2}}+{{y}^{2}}-2xy=0\Rightarrow {{(x-y)}^{2}}=0\Rightarrow y=x\]


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