CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2001

  • question_answer
    The   vertex   of   the   parabola\[{{(y-2)}^{2}}=16(x-1)\]is:

    A)  \[(2,1)\]                             

    B)  \[(1,-2)\]

    C)  \[(-1,2)\]                            

    D) \[(1,2)\]

    Correct Answer: D

    Solution :

    Equation of parabola \[{{(y-2)}^{2}}=16(x-1)\]                 \[{{(y-k)}^{2}}=4a(x-h)\] comparing \[h=1,k=2\]\[4a=16\Rightarrow a=4.\] Therefore vertex of the parabola\[=(1,2).\]


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