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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2001

  • question_answer
    The value of\[\int_{{}}^{{}}{\frac{dx}{{{(x-5)}^{2}}}}\]is:

    A) \[\frac{1}{x-5}+c\]                          

    B)  \[-\frac{1}{x-5}+c\]

    C)  \[\frac{2}{(x+5)}+c\]                     

    D)  none of these

    Correct Answer: B

    Solution :

    \[\int_{{}}^{{}}{\frac{dx}{{{(x-5)}^{2}}}=}\int_{{}}^{{}}{{{(x-5)}^{-1}}dx\Rightarrow \frac{{{(x-5)}^{-2+1}}}{-2+1}}\]\[=-\frac{1}{x-5}+c\]


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