CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2001

  • question_answer
    In order to decompose 9g water \[\text{142}\text{.5 kJ}\]heat is required. Hence the enthalpy of formation of water is:

    A) \[-142.5\,\,kJ\]                 

    B) \[+\,142.5\,kJ\]

    C)  \[-285\,kJ\]                       

    D)  \[+\,285\,kJ\]

    Correct Answer: C

    Solution :

     For the decomposition of 9 gm of water heat required \[=142.5\,\text{kJ}\] We know that the molecular weight of \[{{H}_{2}}O=2+16=18\] Therefore,    heat    required    for decomposition of 18 gm of water \[=\frac{18}{9}\times 142.5=285\,kJ\] Therefore, enthalpy of formation of water \[=-285\,kJ\]


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