CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2001

  • question_answer
    The frequency of a tuning fork is 384 per second and velocity of sound in air is 352 m/s. How far the sound has traversed while fork completes 36 vibration?

    A)  3 m                                       

    B)  13 m

    C)  23 m                                    

    D)  33m

    Correct Answer: D

    Solution :

    Distance traversed in one vibration is \[\lambda =\frac{\upsilon }{n}=\frac{352}{384}\] Distance traversed in 36 vibration \[s=36\lambda =36\times \frac{352}{384}=33\,m\]


You need to login to perform this action.
You will be redirected in 3 sec spinner