A) \[~22.8\text{ }cm/s\]
B) \[~228\text{ }cm/s\]
C) \[16.8\text{ }m/s\]
D) \[~168\text{ }m/s\]
Correct Answer: A
Solution :
Given: Potential at \[A,V=\text{ }600\]volt mass of the ball \[m=1\,gm={{10}^{-3}}kg\] charge on the ball \[q={{10}^{-8}}C\] velocity at B, \[\upsilon B=20\,cm/s\] Now from the relation \[\upsilon _{A}^{2}-\upsilon _{B}^{2}=\frac{2qV}{m}=\frac{2\times {{10}^{-8}}\times 600}{{{10}^{-3}}}=0.012\] Thus \[\upsilon _{A}^{2}=0.012+0.04=0.052\] \[{{\upsilon }_{A}}=0.228\,m/s\] \[{{\upsilon }_{A}}=22.8\,cm/\sec .\]
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