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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2001

  • question_answer
    An ideal gas is taken around PQRP as shown in the figure of PV diagram. The work done during a cycle is:

    A)  zero                                     

    B)  \[\frac{1}{2}PV\]

    C)  PV        

    D)  \[2PV\]

    Correct Answer: C

    Solution :

    The work done during the process from P to \[Q=\]area PQRSTP (positive sign is to be taken due to expansion along PQ) Area of triangle PQR + area of rectangle PRST \[=\frac{1}{2}\times 2\times 1+1\times 2=3\,PV\] Work done during process from R to P \[=-\]Area RSTP (negative sign due to compression in atom RP) \[=-ST\times PT=-2\times 1=-2\,PV\] Hence, the work done in the complete cycle \[=3PV-2PV=PV\]                                


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