CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2000

  • question_answer
    \[\int_{{}}^{{}}{\frac{\sin xdx}{3+4{{\cos }^{2}}x}}\]

    A)  \[\log (3+4{{\cos }^{2}}x)+c\]

    B)  \[-\frac{1}{2\sqrt{3}}{{\tan }^{-1}}\left( \frac{\cos x}{\sqrt{3}} \right)+c\]

    C)  \[-\frac{1}{2\sqrt{3}}{{\tan }^{-1}}\left( \frac{2\cos x}{\sqrt{3}} \right)+c\]

    D)  \[\frac{1}{2\sqrt{3}}{{\tan }^{-1}}\left( \frac{2\cos x}{\sqrt{3}} \right)+c\]

    Correct Answer: C

    Solution :

    \[I=\int_{{}}^{{}}{\frac{\sin xdx}{3+4{{\cos }^{2}}x}}\cos x=t\] \[\Rightarrow -\sin x\,dx=dt\] \[I=-\int_{{}}^{{}}{\frac{dt}{3+4{{t}^{2}}}\Rightarrow I=}-\frac{1}{4}\int_{{}}^{{}}{\frac{dt}{\frac{3}{4}+{{t}^{2}}}}\] \[I=-\frac{1}{4}\int_{{}}^{{}}{\frac{dt}{{{\left( \frac{\sqrt{3}}{2} \right)}^{2}}+{{(t)}^{2}}}}\] \[=-\frac{1}{4}.\frac{2}{\sqrt{3}}{{\tan }^{-1}}\left( \frac{t}{\sqrt{3}/2} \right)+c\] \[=-\frac{1}{2\sqrt{3}}{{\tan }^{-1}}\left( \frac{2\cos x}{\sqrt{3}} \right)+c\]


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