A) \[\text{Hg}{{\text{I}}^{2-}}\]
B) \[\text{HgI}_{4}^{2-}\]
C) \[H{{g}^{+}}\]
D) \[\text{H}{{\text{g}}^{\text{+}\,\text{+}}}\]
Correct Answer: B
Solution :
Nessler's reagent is \[{{\text{K}}_{\text{2}}}\text{Hg}{{\text{I}}_{\text{4}}}\text{.}\]The ion present is \[\text{HgI}_{4}^{2-}.\]
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