CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2000

  • question_answer
    A man suffering from short sight is unable to see objects distinctly at a distance more than 2m. The power of  lens required to correct this defect of the eye should be:

    A) \[~+\,2D\]                          

    B) \[~+\text{ }0.50\,D\]

    C) \[-2D\]                                 

    D) \[-0.5D\]

    Correct Answer: D

    Solution :

    Distance of vision \[\mu =2\,m\] As the man is unable to see distinctly beyond 2 m. Hence, all the objects placed beyond 2 m (i.e.,\[u=\infty \]) must form an image at a distance less or equal to 2 m.                                                                  The relation for focal length of a lens is      \[\frac{1}{f}=\frac{1}{\upsilon }-\frac{1}{u}=\frac{1}{\infty }-\frac{1}{2}=-\frac{1}{2}\]or  \[f=-2m\] Hence, the required power of a lens.


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