A) 34.84%
B) 43.8%
C) 23.4%
D) 21.6%
Correct Answer: A
Solution :
Let the volume of solid Ar = 100 mL Mass of solid \[Ar=V\times \rho =100\times 1.59\,g/c{{m}^{3}}=159\,g\] Volume of liquid Ar \[=\frac{Mass}{\rho }=\frac{159\,\,g}{1.4\,g\,c{{m}^{-3}}}=113.57\,ml\] \[\because \] Ar crystallises in fee type lattice, the packing fraction = 0.74 Actual volume occupied by Ar = Packing fraction \[\times \] Volume of solid Ar \[=0.74\times 100=74\,mL\] \[\therefore \,%\] empty space in liquid\[Ar=\frac{(113.57-74)\times 100}{113.57}\] \[=34.84\,%\]
You need to login to perform this action.
You will be redirected in
3 sec
