A) \[{{(C{{H}_{3}})}_{3}}CCl\]
B) \[{{(C{{H}_{3}})}_{2}}CHCl\]
C) \[{{({{C}_{2}}{{H}_{5}})}_{2}}CHCl\]
D) \[C{{H}_{3}}Cl\]
Correct Answer: D
Solution :
Since, we know that primary halides show inversion during \[{{S}_{N}}2\] reaction more than secondary while secondary show more than tartiary. Therefore, \[C{{H}_{3}}Cl\] (\[{{1}^{o}}\]halide) show sterechemical inversion more in comparison to \[{{(C{{H}_{3}})}_{3}}CCl\] (\[{{3}^{o}}\] halide), \[{{(C{{H}_{3}})}_{2}}\,CHCl\] (\[{{2}^{o}}\]halide) and \[{{({{C}_{2}}{{H}_{5}})}_{2}}CHCl\] (\[{{2}^{o}}\] halide).
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