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BCECE Medical BCECE Medical Solved Papers-2015

  • question_answer
    At \[{{80}^{o}}C\], the vapour pressure of pure liquid A is 520 mm Hg and that of pure liquid B is 1000 mm Hg. If a mixture solution of A and B boils at \[{{80}^{o}}C\]and 1 atm pressure, the amount of A in the mixture is

    A)  50 mol per cent    

    B)  54 mol per cent

    C)  32 mol per cent     

    D)  44 mol per cent

    Correct Answer: A

    Solution :

    Let the amount of A in the mixture be \[{{\chi }_{A}}\] and be \[{{\chi }_{B}}\].                 \[{{p}_{T}}=760={{p}^{o}}_{A}{{\chi }_{A}}+{{p}^{o}}{{\chi }_{B}}\]                 \[760=520{{\chi }_{A}}+1000\,\,(1-{{\chi }_{A}})\]                 \[480{{\chi }_{A}}=240\] \[{{\chi }_{A}}=\frac{1}{2}\] or 50 mol percent


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