BCECE Medical BCECE Medical Solved Papers-2015

  • question_answer
    A U -shaped wire is dipped in a soap solution and removed. The thin soap film formed between the wire and light slider supports a weight of \[1.5\times {{10}^{2}}N\]. The length of the slider is 30 cm. What is the surface tension of the film?

    A)  \[3\times {{10}^{-3}}N{{m}^{-1}}\]      

    B)  \[2\times {{10}^{-5}}N{{m}^{-1}}\]

    C)  \[4\times {{10}^{-4}}N{{m}^{-1}}\]      

    D)  \[2.5\times {{10}^{-2}}N{{m}^{-1}}\]  

    Correct Answer: D

    Solution :

    A soap film has two free surfaces, so total length of the film to be supported,                 \[I=2\times 30\,\,cm=0.60\,m\] Let T = surface tension of the film. If \[f=\] total force on the slider due to surface tension, then                      \[f=T\times 2l=T\times 0.6\,N\]                                 \[W=1.5\times {{10}^{-2}}N\] In equilibrium position, the force / on the slider due to surface tension must be balanced by the weight (w) supported by the slider i.e.,        \[f=w=mg\]                 \[T\times 0.6=1.5\times {{10}^{-2}}\]                 \[T=\frac{1.5\times {{10}^{-2}}}{0.6}\] \[T=2.5\times {{10}^{-2}}\,N{{m}^{-1}}\]


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