A) \[C{{H}_{3}}Br\]
B) \[C{{H}_{3}}CON{{H}_{2}}\]
C) \[C{{H}_{3}}N{{H}_{2}}\]
D) \[CHB{{r}_{3}}\]
Correct Answer: C
Solution :
\[C{{H}_{3}}C{{H}_{2}}Br\xrightarrow[\Delta ]{aq.\,\,KOH}\underset{(A)}{\mathop{C{{H}_{3}}C{{H}_{2}}OH}}\,\xrightarrow[\Delta ]{KMn{{O}_{2}}/{{H}^{+}}}\] \[\underset{\begin{smallmatrix} acetic\text{ }acid \\ (B) \end{smallmatrix}}{\mathop{C{{H}_{3}}COOH}}\,\xrightarrow{N{{H}_{3}}}C{{H}_{3}}COON{{H}_{4}}\xrightarrow{\Delta }\underset{\begin{smallmatrix} acetamide \\ (C) \end{smallmatrix}}{\mathop{C{{H}_{3}}CON{{H}_{2}}}}\,\] \[\xrightarrow{B{{r}_{2}}/Alkali}\underset{\begin{smallmatrix} methyl\text{ }amine \\ (D) \end{smallmatrix}}{\mathop{C{{H}_{3}}N{{H}_{2}}}}\,\]
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