A) 0.0355 g
B) 0.071 g
C) \[6.023\times {{10}^{21}}\] molecules
D) 0.02 mol
Correct Answer: A
Solution :
Ideal gas equation is \[pV=nRT\] When V and 7 are same, \[p\propto n\] Thus, when number of moles, i.e., n is least, it will exert least pressure. [a] \[n=\frac{wt}{mol.\,\,wt}=\frac{0.0355}{35.5}=1\times {{10}^{-3}}mol\] [b] \[n=\frac{0.071}{35.5}=2\times {{10}^{-3}}mol\] [c] \[n=\frac{number\text{ }or\text{ }molecules}{{{N}_{A}}}\] \[=\frac{6.023\times {{10}^{21}}}{6.023\times {{10}^{23}}}=0.01\,\,mol\] [d] \[n=0.02\,mol\] Thus, 0.0355 g chlorine will exert the least pressure.
You need to login to perform this action.
You will be redirected in
3 sec
