| Column - I | Column - II | ||
| [a] | Potential of hydrogen electrode at pH = 10 | (i) | 0.76 V |
| [b] | \[C{{u}^{2+}}\left| Cu \right.\] | (ii) | 0.059 |
| [c] | \[Zn\left| Z{{n}^{2+}} \right.\] | (iii) | -0.591V |
| [d] | \[\frac{2.303\,\,RT}{F}\] | (iv) | 0.337 V |
| (v) | -0.76V |
A) A- (III) B-(I) C-(II) D- (V)
B) A-(II) B- (V) C-(I) D-(IV)
C) A-(III) B-(IV) C-(I) D-(II)
D) A- (V) B-(I) C-(IV) D-(II)
Correct Answer: C
Solution :
Potential of hydrogen electrode at \[pH=10\] is - 0.591V. Reduction potential of \[C{{u}^{2+}}/Cu\] is 0.36 V. Oxidation potential of \[Zn/Z{{n}^{2+}}\] is 0.76 V. \[\frac{2.303\,RT}{F}=\frac{2.303\times 8.314\times 298}{96500}=0.059\]
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