A) \[p{{K}_{a}}-\log 2\]
B) \[p{{K}_{a}}\]
C) \[p{{K}_{a}}+2\]
D) \[p{{K}_{a}}+\log 2\]
Correct Answer: D
Solution :
Initially \[[C{{H}_{3}}COONa]=0.1\,\,mol\] \[[C{{H}_{3}}COOH]=0.1\,\,mol\] When \[0.1\,\,mol\,\,C{{H}_{3}}COONa\] is added. \[[C{{H}_{3}}COONa]=0.1+0.1=0.2\,mol\] \[pH=p{{K}_{a}}+\log \frac{[salt]}{[acid]}\] \[=p{{K}_{a}}+\log \frac{0.2}{0.1}=p{{K}_{a}}+\log \,2\]
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