| I. \[F{{e}^{2+}}\] |
| II. \[T{{i}^{2+}}\] |
| III. \[C{{u}^{2+}}\] |
| IV. \[{{V}^{2+}}\] |
A) I. II, IV, III
B) IV, 1. II, III -
C) III. IV, I, II
D) lll, II, IV, I
Correct Answer: D
Solution :
Magnetic moment \[(\mu )\] is given as \[\mu =\sqrt{n\,(n+2)}\] where, n is number of unpaired electrons. \[F{{e}^{2+}}:\,[Ar]3{{d}^{6}};\] number of unpaired electrons = 4 \[T{{i}^{2+}}:\,[Ar]3{{d}^{2}};\] number of unpaired electrons = 2 \[C{{u}^{2+}}:\,[Ar]3{{d}^{9}};\] number of unpaired electrons = 1 \[{{V}^{2+}}:\,[Ar]3{{d}^{3}};\] number of unpaired electrons = 3 Hence, the increasing order of magnetic moment is as \[C{{u}^{2+}}<T{{i}^{2+}}<{{V}^{2+}}<F{{e}^{2+}}\]
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