A) \[\pi \]
B) \[\frac{\pi }{5}\]
C) \[\frac{\pi }{10}\]
D) \[2\pi \]
Correct Answer: C
Solution :
\[E=\frac{1}{2}l{{\omega }^{2}}\] \[\omega =\sqrt{\frac{2E}{l}}=\sqrt{\frac{2\times 600}{3}}=20\] \[\omega =\frac{2\pi }{T}=20\Rightarrow T=\frac{\pi }{10}\]
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