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  3. BCECE Medical

BCECE Medical BCECE Medical Solved Papers-2014

  • question_answer
    In a circular coil (1) of radius R, current I is flowing and in another coil (2) of radius 2R a current \[2I\] is flowing, then the ratio of the magnetic fields produced by the two coils is

    A)  1 : 1                

    B)  1 : 2

    C)  2 : 1                 

    D)  3 : 1

    Correct Answer: A

    Solution :

    Magnetic field for coil 1                 \[{{B}_{1}}=\frac{{{\mu }_{0}}Nl}{2R}\] Magnetic field for coil 2                 \[{{B}_{2}}=\frac{{{\mu }_{0}}N(2l)}{2(2R)}=\frac{{{\mu }_{0}}Nl}{2R}\] \[\therefore \] \[\frac{{{B}_{1}}}{{{B}_{2}}}=\frac{1}{1}\]


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