A) 50 %
B) 11.5 %
C) 4.01 %
D) 1.19 %
Correct Answer: B
Solution :
Theoretical value of dipole moment of 100% ionic character \[=e\,\,\,\times d\] \[=(1.6\times {{10}^{-19}}C)\,\,(1.4\times {{10}^{-10}}m)\] \[=2.26\times {{10}^{-29}}\,Cm\] Observed value of dipole moment \[=2.60\times {{10}^{-30}}Cm\] \[\therefore \] Per cent ionic character \[=\frac{observed\text{ }value}{theoretical\text{ }value}\times 100\] \[=\frac{2.60\times {{10}^{-30}}}{2.26\times {{10}^{-29}}}\times 100\] = 11.5%
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