A)
B)
C)
D)
Correct Answer: C
Solution :
For a long conductor, magnetic field at distance r is \[B=\frac{{{\mu }_{0}}}{4\pi }\times \frac{2l}{r}=\frac{{{\mu }_{0}}l}{2\pi r}\] \[\therefore \] \[B\propto \frac{1}{r}\] So, graph between B and r should be a parabola as given in option [c].
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