A) \[\frac{{{P}_{e}}}{{{P}_{Pn}}}=\frac{C}{2v}\]
B) \[\frac{{{E}_{e}}}{{{E}_{Pn}}}=\frac{C}{2v}\]
C) \[\frac{{{E}_{ph}}}{{{E}_{e}}}=\frac{2C}{v}\]
D) \[\frac{{{P}_{e}}}{{{P}_{ph}}}=\frac{2C}{v}\]
Correct Answer: C
Solution :
We have , \[{{\lambda }_{Ph}}=\frac{h}{{{P}_{ph}}}\] and \[{{\lambda }_{e}}=\frac{h}{{{P}_{e}}}\] Given, \[{{\lambda }_{Ph}}={{\lambda }_{e}}\] \[\therefore \] We get, \[{{P}_{Ph}}={{P}_{e}}\] \[\frac{h}{{{\lambda }_{Ph}}}=mv\] \[\therefore \] \[\frac{hc}{{{\lambda }_{Ph}}}=mcv=\frac{1}{2}\left( \frac{2c}{v} \right)\] or \[\frac{{{E}_{Ph}}}{{{E}_{e}}}=\frac{2c}{v}\]
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