A) \[40\,\pi \,m/{{s}^{2}}\]
B) \[40\,m/{{s}^{2}}\]
C) \[160\,\pi \,m/{{s}^{2}}\]
D) \[640\,\pi \,m/{{s}^{2}}\]
Correct Answer: B
Solution :
We have, \[{{v}^{2}}={{u}^{2}}+2as\] \[\Rightarrow \] \[{{(80)}^{2}}=0+2\,\,(a)\,\left( 4\pi \times \frac{20}{\pi } \right)\] [as two revolutions are completed] \[\Rightarrow \] \[a=40\,m/{{s}^{2}}\]
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