A) Zn act as oxidising agent when react with \[HN{{O}_{3}}\]
B) \[HN{{O}_{3}}\] is weaker acid than \[{{H}_{2}}S{{O}_{4}}\] and \[HCl\]
C) in electrochemical series Zn is above hydrogen
D) \[NO_{3}^{-}\] is reduced in preference to hydronium ion
Correct Answer: D
Solution :
Zn is present above \[{{H}_{2}}\] in electrochemical series. So, it liberates hydrogen gas from dilute\[HCl/{{H}_{2}}S{{O}_{4}}\]. But \[HN{{O}_{3}}\] is a strong oxidising agent so it oxidises the hydrogen obtained into\[{{H}_{2}}O\]. In \[HN{{O}_{3}},NO_{3}^{-}\] ion is reduced and give\[N{{H}_{4}}N{{O}_{3}},{{N}_{2}}O\], NO and \[N{{O}_{2}}\] (based upon the concentration of \[HN{{O}_{3}}\]). \[4Zn+10HN{{O}_{3}}\xrightarrow{{}}4Zn{{(N{{O}_{3}})}_{2}}\] \[+N{{H}_{4}}N{{O}_{3}}+3{{H}_{2}}O\]
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