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BCECE Medical BCECE Medical Solved Papers-2012

  • question_answer
    Solution of \[0.1\,N\,N{{H}_{4}}OH\] and \[0.1\,N\,N{{H}_{4}}Cl\] has \[pH\,9.25\], then find out \[p{{K}_{b}}\] of \[N{{H}_{4}}OH\].

    A)  9.25          

    B)  4.75

    C)  3.75          

    D)  8.25

    Correct Answer: B

    Solution :

    Solution of \[N{{H}_{4}}OH\] and \[N{{H}_{4}}Cl\] acts as a basic buffer solution. For basic buffer solution,                 \[pOH=p{{K}_{b}}+\log \frac{[Salt]}{[Base]}\]                 \[pOH=14-pH=14-9.25=4.75\]                 \[4.75=p{{K}_{b}}+\log \frac{0.1}{0.1}\] \[p{{K}_{b}}=4.75\]


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