BCECE Medical BCECE Medical Solved Papers-2012

  • question_answer
    A human body required the 0.01 M activity of radioactive substance after 24 h. Half-life of radioactive substanu is 6 h. Then injection of maximum activity of radioactive substance that can be injected

    A)  0.08           

    B)  0.04

    C)  0.16        

    D)  0.32

    Correct Answer: C

    Solution :

    Remaining activity = 0.01 M after 24 h Remaining activity                 \[=Initial\text{ }activity\times {{\left( \frac{1}{2} \right)}^{n}}\] Used half-life time (n)                 \[=\frac{Total\text{ }time}{{{T}_{1/2}}}=\frac{24}{6}=4\] So, 0.01 = Initial activity \[\times {{\left( \frac{1}{2} \right)}^{4}}\] Initial activity \[=0.1\times 1.6=0.16\]


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