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BCECE Medical BCECE Medical Solved Papers-2012

  • question_answer
    When 1 mole gas is heated at constant volume, temperature is raised from 298 K to 308K. Heat supplied to the gas is 500 J. Then which statement is correct?

    A)  \[q=w=500\,J,\,\,\Delta U=0\]

    B)  \[q=\Delta U=500\,J,w=0\]

    C)  \[q=W=500\,J,\Delta U=0\]

    D)  \[\Delta U=0,\,\,q=W=-500\,J\]

    Correct Answer: B

    Solution :

    As we know that \[\Delta H=\Delta E+p\Delta V\]  When    \[\Delta V=0\] \[\therefore \] \[\Delta H=\Delta E\] From first law of thermodynamics                 \[\Delta U=q+W\] In the given problem, \[\Delta H=500\,J\]                 \[-W=-p\Delta V,\Delta V=0\] So, \[\Delta U=q=500\,J\]


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