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BCECE Medical BCECE Medical Solved Papers-2012

  • question_answer
    If the displacement equation of a particle from its mean position is given as   \[y=0.2\sin \,(10\pi t+1.5\pi )cos(10\pi t+1.5\pi )\] then, the motion of particle is

    A)  anon-periodic

    B)  periodic but not SHM

    C)  SHM with period 0.2 s

    D)  SHM with period 0.1 s

    Correct Answer: D

    Solution :

    Given, \[y=0.2\sin \,(10\pi t+1.5\pi )\cos (10\pi t+1.5\pi )\]                 \[=0.1\sin 2(10\pi t+1.5\pi )\]                                 \[[\,\,\,\,\sin 2A=2\sin A\cos A]\]                 \[=0.1\sin (20\pi t+3.0\pi )\] So, the motion of particle is SHM Time period, \[T=\frac{2\pi }{\omega }=\frac{2\pi }{20\pi }=\frac{1}{10}=0.1\,\,s\]


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