A) 4 cm
B) 8 cm
C) 25 cm
D) 12.5 cm
Correct Answer: C
Solution :
On comparing the given equation with \[y=a\cos (\omega \,t+kx-\phi )\] we get, \[k=\frac{2\pi }{\lambda }=0.02\] and \[\lambda =100\,cm\] It is given that phase difference between particles, \[\Delta \phi =\frac{\pi }{2}\] So, the path difference between them, \[\Delta \,p=\frac{\lambda }{2\pi }\times \Delta \phi \] \[=\frac{\lambda }{2\pi }\times \frac{\pi }{2}=\frac{\lambda }{4}\] \[=\frac{100}{4}=25\,\,cm\]
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