A) acetaldehyde oxime
B) formaldehyde oxime
C) methyl nitrate
D) acetoxime
Correct Answer: D
Solution :
\[2C{{H}_{3}}COOH\xrightarrow{CaC{{O}_{3}}}\underset{A}{\mathop{{{(C{{H}_{3}}COO)}_{2}}Ca}}\,\xrightarrow[-CaC{{O}_{3}}]{\Delta }\]\[C{{H}_{3}}COC{{H}_{3}}\xrightarrow[-{{H}_{2}}O]{N{{H}_{2}}OH}C{{H}_{3}}\underset{\begin{align} & || \\ & NaOH \\ & acetoxime \\ & C \\ \end{align}}{\mathop{C}}\,-C{{H}_{3}}\]
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