A) \[{{K}_{1}}=2{{K}_{2}}\]
B) \[{{K}_{1}}=\frac{1}{2}{{K}_{2}}\]
C) \[{{K}_{2}}=\sqrt{{{K}_{1}}}\]
D) \[{{K}_{1}}={{K}_{2}}\]
Correct Answer: C
Solution :
\[{{N}_{2}}+3{{H}_{2}}\,2N{{H}_{3}}\] \[{{({{K}_{C}})}_{1}}=\frac{{{[N{{H}_{3}}]}^{2}}}{[{{N}_{2}}]\,{{[{{H}_{2}}]}^{3}}}\] ?. (i) \[\frac{1}{2}{{N}_{2}}+\frac{3}{2}{{H}_{2}}N{{H}_{3}}\] \[{{({{K}_{C}})}_{2}}=\frac{[N{{H}_{3}}]}{{{[{{N}_{2}}]}^{1/2}}{{[{{H}_{2}}]}^{3/2}}}\] ?. (ii) From Eqs. (i) and (ii), we get \[\frac{{{({{K}_{C}})}_{1}}}{{{({{K}_{C}})}_{2}}}=1\] \[{{({{K}_{C}})}_{2}}=\sqrt{{{({{K}_{C}})}_{1}}}\]
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