A) diacetoneamine
B) pinacol
C) chloretone
D) propane
Correct Answer: B
Solution :
Bimolecular reduction of acetone gives pinacol. \[\underset{acetone}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\mathop{C}}\,}}\,+\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\mathop{C}}\,}}\,-C{{H}_{3}}}}\,\] \[\xrightarrow{Mg-Hg,\,\,{{H}_{2}}}\underset{\begin{smallmatrix} 2,\text{ }3-dimethyl-2,3- \\ butanediol\text{ (}pinacol\text{)} \end{smallmatrix}}{\mathop{{{H}_{3}}C-\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C}}\,}}\,-\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C}}\,}}\,-C{{H}_{3}}}}\,\]
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