A) propanal
B) ethanoic acid
C) propanone
D) ethanol
Correct Answer: B
Solution :
\[\underset{propan-2-ol}{\mathop{C{{H}_{3}}CHOHC{{H}_{3}}}}\,\xrightarrow{[O]}\underset{acetone}{\mathop{C{{H}_{3}}COC{{H}_{3}}}}\,\] \[\xrightarrow{[O]}\underset{\begin{smallmatrix} acetic\text{ }acid \\ or\text{ }ethanoic \\ acid \end{smallmatrix}}{\mathop{C{{H}_{3}}COOH}}\,\,\,+C{{O}_{2}}+{{H}_{2}}O\]
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