BCECE Medical BCECE Medical Solved Papers-2011

  • question_answer
    If \[x\,mol\,\,{{L}^{-1}}\] is the solubility of \[KAl{{(S{{O}_{4}})}_{2}}\] then \[{{K}_{sp}}\] is equal to

    A)  \[{{x}^{3}}\]

    B)  \[4{{x}^{4}}\]

    C)  \[{{x}^{4}}\]

    D)  \[4{{x}^{3}}\]

    Correct Answer: B

    Solution :

    \[KAl{{(S{{O}_{4}})}_{2}}\xrightarrow{{}}\underset{+}{\mathop{{{K}^{+}}}}\,+{{\underset{+}{\mathop{Al}}\,}^{3+}}+\underset{2x}{\mathop{2SO_{4}^{2-}}}\,\]                 \[{{K}_{sp}}=[{{K}^{+}}]\,[A{{l}^{3+}}]\,{{[SO_{4}^{2-}]}^{2}}\] \[=(x)\,(x)\,{{(2x)}^{2}}=4{{x}^{4}}\]


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