A) \[{{40}^{o}}\,18\]
B) \[{{24}^{o}}\,49\]
C) \[{{25}^{o}}\,17\]
D) \[{{35}^{o}}\,16\]
Correct Answer: D
Solution :
\[i={{\sin }^{-1}}\left( \frac{\sqrt{3}}{2} \right)={{\sin }^{-1}}(\sin {{60}^{o}})={{60}^{o}}\] \[\mu =\frac{\sin i}{\sin r}\] \[\Rightarrow \] \[\sin r=\frac{\sin i}{\mu }=\frac{\sin {{60}^{o}}}{1.5}=\frac{0.8660}{1.5}\] \[\sin r=0.5773\] \[r={{\sin }^{-1}}(0.5773)={{35}^{o}}16\]
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