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  3. BCECE Medical

BCECE Medical BCECE Medical Solved Papers-2011

  • question_answer
    A wire has a breaking stress of \[6\times {{10}^{5}}N/{{m}^{2}}\] and a density of \[3\times {{10}^{4}}kg/{{m}^{3}}\]. The length of the wire of the same material which will break under its own weight, (if \[g=10\,m/{{s}^{2}}\]) is

    A)  2000m        

    B)  2500m

    C)  20m           

    D)  2m

    Correct Answer: D

    Solution :

    Breaking stress is given by \[=6\times {{10}^{5}}N/{{m}^{2}}=\frac{mg}{A}\]                  (But \[m=AL\rho \]) \[6\times {{10}^{5}}=\frac{AL\rho g}{A}=L\rho g\] Thus, \[L=\frac{6\times {{10}^{5}}}{\rho g}\]\[=\frac{6\times {{10}^{5}}}{3\times {{10}^{4}}\times 10}=2m\]


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