BCECE Medical BCECE Medical Solved Papers-2011

  • question_answer
    A 4 m long wire of resistance \[8\,\Omega \]  is connected in series with a battery of emf 2 V and a resistor of \[7\,\Omega \]. The internal resistance of the battery is \[1\,\,\Omega \]. What is the potential gradient along the wire?

    A)  1, 00 \[V{{m}^{-1}}\]

    B)  0,75 \[V{{m}^{-1}}\]

    C)  0.50 \[V{{m}^{-1}}\]      

    D)  0.25 \[V{{m}^{-1}}\]

    Correct Answer: D

    Solution :

    Current in the potentiometer                 \[i=\frac{2}{8+7+1}=\frac{1}{8}A\] Voltage drop across potentiometer wire                 \[=\frac{1}{8}\times 8=1\,\,V\] \[\therefore \] Potential gradient of potentiometer wire \[=\frac{1}{4}=0.25\,V/m\]


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