If an artificial satellite is moving in a circular orbit around the earth with a speed equal to half the magnitude of the escape velocity from the earth, the height of the satellite above the surface of the earth is
A) 2R
B) R
C) R
D) R
Correct Answer:
C
Solution :
According to question, \[\sqrt{\frac{GM}{R+h}}=\frac{1}{2}\sqrt{\frac{2GM}{R}}\] h = R