A) \[{{({{C}_{2}}{{H}_{5}})}_{3}}N<{{({{C}_{2}}{{H}_{5}})}_{2}}NH<{{C}_{2}}{{H}_{5}}N{{H}_{2}}\]
B) \[({{C}_{2}}{{H}_{5}})N{{H}_{2}}<{{({{C}_{2}}{{H}_{5}})}_{2}}NH<{{({{C}_{2}}{{H}_{5}})}_{3}}N\]
C) \[{{({{C}_{2}}{{H}_{5}})}_{2}}NH<{{C}_{2}}{{H}_{5}}N{{H}_{2}}<{{({{C}_{2}}{{H}_{5}})}_{3}}N\]
D) \[{{({{C}_{2}}{{H}_{5}})}_{3}}N<{{C}_{2}}{{H}_{5}}N{{H}_{2}}<{{({{C}_{2}}{{H}_{5}})}_{2}}NH\]
Correct Answer: B
Solution :
Chlorobenzene is a non-polar solvent, thus amines follow their general trend of basicity, ie, as the number of alkyl groups increases, availability of lone pair for donation decreases, and thus basicity increases. \[\therefore \] The order of basic strength is \[{{C}_{2}}{{H}_{5}}N{{H}_{2}}<{{({{C}_{2}}{{H}_{5}})}_{2}}NH<{{({{C}_{2}}{{H}_{5}})}_{3}}N\]
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