BCECE Medical BCECE Medical Solved Papers-2010

  • question_answer
    Consider the following \[{{E}^{o}}\] values \[E_{F{{e}^{3+}}/F{{e}^{2+}}}^{o}=+0.77\,\,V\] \[E_{S{{n}^{2+}}/Sn}^{o}=-0.14\,\,V\] Under standard conditions the potential for the reaction, \[Sn(s)+2F{{e}^{3+}}(aq)\xrightarrow{{}}2F{{e}^{2+}}(aq)+S{{n}^{2+}}(aq)\] is

    A)  1.68 V

    B)  1.40 V

    C)  0.91 V          

    D)  0.63 V

    Correct Answer: C

    Solution :

    \[Sn(s)+2F{{e}^{3+}}(aq)\xrightarrow{{}}2F{{e}^{2+}}(aq)+S{{n}^{2+}}(aq)\]                 \[E_{cell}^{o}=E_{ox}^{o}+E_{red}^{o}\]                 \[=E_{Sn/S{{n}^{2+}}}^{o}+E_{F{{e}^{3+}}/F{{e}^{2+}}}^{o}\] Given    \[E_{S{{n}^{2+}}/Sn}^{o}=-0.14\,\,V\] \[\therefore \] \[E_{Sn/S{{n}^{2+}}}^{o}=+\,0.14\,\,V\]                 \[E_{F{{e}^{3+}}/F{{e}^{2+}}}^{o}=\,0.77\,\,V\] \[\therefore \] \[E_{cell}^{o}=01.4+0.77=0.91\,\,V\]


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