question_answer

The ONO angle is maximum in

A)  \[NO_{3}^{-}\]         

B)  \[NO_{2}^{-}\]

C)  \[N{{O}_{2}}\]

D)  \[NO_{2}^{+}\]

Correct Answer: D

Solution :

In \[NO_{3}^{-}\], N atom undergoes \[s{{p}^{2}}\]-hybridisation. Thus, the ion has trigonal planar geometry with bond angle \[{{120}^{o}}C\].                                 \[NO_{2}^{-}\] has angular geometry (\[s{{p}^{2}}\]hybridisation) due to presence of one lone pair of electrons on N atom. Bond angle is \[{{116}^{o}}\]. \[N{{O}_{2}}\] has angular geometry (\[s{{p}^{2}}\]hybridisation) with bond angle \[{{134}^{o}}\]. \[NO_{2}^{+}\] (nitronium ion) has linear structure (sp hybridisation) with bond angle \[{{180}^{o}}\]. \[\therefore \] The bond angle is maximum in\[NO_{2}^{+}\], ie,\[{{180}^{o}}\].