A) \[{{(C{{H}_{3}})}_{2}}CHCOOC{{H}_{3}}\]
B) \[{{(C{{H}_{3}})}_{2}}COOCH{{(C{{H}_{3}})}_{2}}\]
C) \[C{{H}_{3}}COOC{{H}_{2}}C{{H}_{3}}\]
D) \[{{(C{{H}_{3}})}_{2}}CHCOOC{{H}_{2}}C{{H}_{3}}\]
Correct Answer: B
Solution :
\[\underset{ethanoic\text{ }acid}{\mathop{C{{H}_{3}}COOH}}\,+\underset{propan\text{ }-2-ol}{\mathop{HOCH\,{{(C{{H}_{3}})}_{2}}}}\,\] \[\xrightarrow{{{H}_{2}}S{{O}_{4}}}\,\underset{iso-propyi\text{ }ethanoate}{\mathop{C{{H}_{3}}COOCH\,{{(C{{H}_{3}})}_{2}}}}\,\] This reaction is called esterification as ester is the final product.
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