BCECE Medical BCECE Medical Solved Papers-2009

  • question_answer
    A parallel plate capacitor of plate area A has a charge Q. The force on each pi ate of the capacitor is

    A)  \[\frac{2{{Q}^{2}}}{{{\varepsilon }_{0}}A}\]

    B)  \[\frac{{{Q}^{2}}}{{{\varepsilon }_{0}}A}\]

    C)  \[\frac{{{Q}^{2}}}{2{{\varepsilon }_{0}}A}\]

    D)  zero

    Correct Answer: C

    Solution :

    Force on one plate due to another is                 \[F=QE=Q\times \frac{\sigma }{2\,\,{{\varepsilon }_{0}}}\]                 \[=Q\left[ \frac{Q}{2A{{\varepsilon }_{0}}} \right]\] \[=\frac{{{Q}^{2}}}{2A{{\varepsilon }_{0}}}\]


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