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BCECE Medical BCECE Medical Solved Papers-2009

  • question_answer
    Two masses \[{{m}_{1}}\] and \[{{m}_{2}}\] are suspended together by a massless spring of force constant k, as shown in figure. When the masses are in equilibrium, mass \[{{m}_{1}}\], is removed without disturbing the system. The angular frequency of oscillation of mass \[{{m}_{2}}\] is                            

    A)  \[\sqrt{\frac{k}{{{m}_{2}}}}\]

    B)  \[\sqrt{\frac{k}{m1}}\]

    C)  \[\sqrt{\frac{k{{m}_{1}}}{m_{2}^{2}}}\]

    D)  \[\sqrt{\frac{k{{m}_{2}}}{m_{1}^{2}}}\]

    Correct Answer: A

    Solution :

    With mass \[{{m}_{2}}\] alone, the angular frequency\[\omega =\sqrt{\frac{k}{{{m}_{2}}}}\]


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