A) \[\frac{1}{4}\]
B) 4
C) 2
D) \[\frac{1}{2}\]
Correct Answer: A
Solution :
Root mean square velocity \[{{v}_{rms}}=\sqrt{\frac{3RT}{M}}\] For constant temperature \[{{v}_{rms}}\propto \frac{1}{\sqrt{M}}\] So, \[\frac{{{({{v}_{rms}})}_{{{O}_{2}}}}}{{{({{v}_{rms}})}_{{{H}_{2}}}}}=\sqrt{\frac{{{M}_{{{H}_{2}}}}}{{{M}_{{{O}_{2}}}}}}\] \[=\sqrt{\frac{2}{32}}=\frac{1}{4}\]
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